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Wonter-记录着一些Coding的小事情 | wonter.net Reviews
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记录着一些Coding的小事情
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Wonter-记录着一些Coding的小事情
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LeetCode 109. Convert Sorted List to Binary Search Tree. 题意 给出一个有序链表，构造出一个平衡二叉树 (AVL) 思路 那么跟 LeetCode 108. Convert Sorted Array to Binary Search Tree 一样的做法，每次取中间的数为根，左右递归即可 解决代码 /* * Definitio. LeetCode 108. Convert Sorted Array to Binary Search Tree. 题意 给出一个有序数组，构造出一个平衡二叉树(AVL) 思路 由于数组是有序的，所以我们每次选择中间的元素作为根，左边的为左子树，右边的为右子树，然后递归构建就好了 解决代码 /* * Definition for a binary tree node. * stru. LeetCode 71. Simplify Path. LeetCode 65. Valid Number. LeetCode 107. Binary Tree Level Order Traversal II.
LeetCode - 刷题日记 - Wonter
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LeetCode 110. Balanced Binary Tree - Wonter
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LeetCode 110. Balanced Binary Tree. 题意 给出一个树，判断是否为平衡二叉树 AVL # # 思路 递归求出左子树的高度和右子树的高度，然后判断相差是否为1 再判断左子树和右子树是否也是AVL即可 # # 解决代码 ` `cpp /* * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: bool isBalanced(TreeNode* root) { return height(root)!
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Wonter-记录着一些Coding的小事情
前言 要准备开始刷LeetCode系统的复习一遍数据结构了 题目代码会同步到我的github仓库，语言为C 但题目的详细题解会在博客发布，并在此页面汇总 一些心得 记录一下遇到题目应该思考的问题 给出的数组或者链表为空的时候应该怎样，某些边界情况应该怎样 计算中间的数. A - Scc Puzzle 题意 两个C可以拼成一个S，现在有n个S和m个C，最多可以组成多少个SCC 思路 S不够，拿C来凑 显然4个C可以凑成一个SCC 所以可以贪心的构成最多的SCC，为了节省C，首先当然不会用C去构成S，而是先用现有的S，一个S和2个C组合。 今天coding时需要打开1024个文件，然而我每次打开到509个的时就会失败 经过一番搜索最终找到了解决的办法 windows下默认会限制打开文件的数量，如果我们想要提高这个数量可以使用 setmaxstdio这个函数，在cstdio头文件中 如果设置成功则返回新的打开数. LeetCode 110. Balanced Binary Tree. LeetCode 109. Convert Sorted List to Binary Search Tree.
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